WebExpert Answer. Transcribed image text: For the equation x2 + y2 - 4x - 2y – 31 = 0. do the following. (a) Find the center (h,k) and radius r of the circle. (b) Graph the circle. (c) Find the intercepts, if any. (a) The center is 1 (Type an ordered pair.) The radius is re (b) Use the graphing tool to graph the circle. WebHInt: 2x^2+x(2y)+y^2-2y+2=0 As x is real, the discriminant must be \ge0 (2y)^2-8(y^2-2y+2)\ge0\iff0\ge-4(y-2)^2\iff(y-2)^2\le0 But as y is real, (y-2)^2\ge0 How do you find the …
Centre radius form of equation of circle and its use - The Fact Factor
WebJan 17, 2024 · radius = 2 Explanation: The standard equation of a circle with centre (a,b), and radius r is: (x − a)2 +(y −b)2 = r2 so for : x2 + y2 +4x − 2y = − 1 we will have to complete the square before we can identify the radius. x2 +y2 + 4x −2y = − 1 x2 +4x + y2 −2y = − 1 (x2 + 4x) +(y2 − 2y) = − 1 (x2 + 4x + 22) − 22 +(y2 − 2y +12) − 12 = −1 WebNov 23, 2016 · Intersection points are (1,-1) and (4,2) and tangents are x+2y+1=0 and 2x+y=10 x^2+y^2-4x-2y=0 an be written as (x-2)^2+(y-1)^2=5 and hence is a circle with center at (2,1) and radius sqrt5. For finding intersection point between x^2+y^2-4x-2y=0 and line y=x-2, we can put y=x-2 in the equation x^2+y^2-4x-2y=0. Doing this, we get x^2+(x … buy whilesale mangos surrey
[Solved] Radius of the circle x2 + y2 – 4x + 2y – 31 = 0
WebSep 3, 2012 · You're trying to make this look like the equation for a circle which has the two square binomials set equal to the radius. Anyway, since both coefficients are 2, simply divide the whole thing by two. x 2 + 4x + (____) + y 2 - 6y + (____) = 12 Now look at the x term, 4x. WebFeb 3, 2024 · Ans: The required equation of circle is x 2 + y 2 – 4x + 2y – 45 = 0. Example 09: Find the equation of circle having centre at (2, -3) and passing through P(-3, 5) ... Find equation of a circle having centre at (- 4, 0) and radius 5. Ans: x2 + y2 + 8x – 34 = 0 6. Find equation of a circle having centre at (7, 2) and radius 3. Ans: x2 + y2 ... WebSep 30, 2016 · Explanation: x2 +y2 − 4x +12y − 36 = 0. Rearrange the terms by grouping the x terms, grouping the y terms, and moving the constant term to the other side. x2 −4xaaa + y2 +12yaaa = 36aaa. Complete the square for x terms and the y terms. To complete the square for the x terms, divide the coefficient of the "middle term" 4x by 2, square the ... buy whey